# How do you find w(t-1) given w(t)=t^2-4?

Jan 15, 2017

The answer is $= \left(t + 1\right) \left(t - 3\right)$

#### Explanation:

Replace $t$ by $\left(t - 1\right)$

$w \left(t\right) = {t}^{2} - 4$

$w \left(t - 1\right) = {\left(t - 1\right)}^{2} - 4 = {t}^{2} - 2 t + 1 - 4$

$= {t}^{2} - 2 t - 3 = \left(t + 1\right) \left(t - 3\right)$