How do you finish the reaction: #Br_2(g) + KCl(aq) ->#?

1 Answer
May 12, 2018

Answer:

There is no need.

Explanation:

Bromine is not a sufficiently strong oxidiser to displace chloride ions. This gives:

#sf(Br_(2(g))+KCl_((aq))rarr"no reaction")#