How do you finish the reaction: #Br_2(g) + KCl(aq) ->#?

1 Answer
Michael
May 12, 2018

There is no need.

Explanation:

Bromine is not a sufficiently strong oxidiser to displace chloride ions. This gives:

#sf(Br_(2(g))+KCl_((aq))rarr"no reaction")#

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