How do you finish the reaction: #Zn(s) + CuSO_4(aq) ->#?

1 Answer
Apr 8, 2017

Answer:

#->ZnSO_4(aq)+Cu(s)#

Explanation:

Zinc, being the less noble metal of the two, will donate two electrons to the copper(II)-ions:

#Zn(s)+Cu^(2+)(aq)->Zn^(2+)(aq)+Cu(s)#