How do you fully factor #4x^2-6xy#?

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Answer 1 · 2018-03-19T09:22:37

#2x(2x-3y)#

we take out the hcf from each term
so

#hcf(4,6)=2#

#hcf(x^2,x)=x#

#:. 4x^2-6xy=2x(2x-3y)#

Answer 2 · 2018-03-19T09:24:17

#4x^2-6xy=2x(2x-3y)#

Factor out the common term. Here the common term is 2x.

Thus,

#4x^2-6xy=2x(2x-3y)#