Question

How do you get rid of the outer exponent of `(\frac { 5a b ^ { 4} } { c ^ { 7} } ) ^ { 2}`?

Answer 1

See the entire solution process below:

Explanation:

Use these rules for exponents to get rid of the outer exponent:

`a = a^color(red)(1)` and `(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))`

`((5ab^4)/c^7)^2 = ((5^color(red)(1)a^color(red)(1)b^color(red)(4))/c^color(red)(7))^color(blue)(2) = ((5^(color(red)(1)xxcolor(blue)(2))a^(color(red)(1)xxcolor(blue)(2))b^(color(red)(4)xxcolor(blue)(2)))/c^(color(red)(7)xxcolor(blue)(2))) = (5^2a^2b^8)/c^14 =`

`(25a^2b^8)/c^14`