# How do you graph 1.5x + y = 4 ?

Oct 14, 2017

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$\left(1.5 \cdot 0\right) + y = 4$

$0 + y = 4$

$y = 4$ or $\left(0 , 4\right)$

Second Point: For $x = 2$

$\left(1.5 \times 2\right) + y = 4$

$3 + y = 4$

$- \textcolor{red}{3} + 3 + y = - \textcolor{red}{3} + 4$

$0 + y = 1$

$y = 1$ or $\left(2 , 1\right)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -2, 8]}

Now, we can draw a straight line through the two points to graph the line:

graph{(1.5x + y - 4)(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -2, 8]}