How do you graph #1.5x + y = 4 #?

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Answer 1 · 2017-10-14T18:12:58

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(1.5 * 0) + y = 4#

#0 + y = 4#

#y = 4# or #(0, 4)#

Second Point: For #x = 2#

#(1.5 xx 2) + y = 4#

#3 + y = 4#

#-color(red)(3) + 3 + y = -color(red)(3) + 4#

#0 + y = 1#

#y = 1# or #(2, 1)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -2, 8]}

Now, we can draw a straight line through the two points to graph the line:

graph{(1.5x + y - 4)(x^2+(y-4)^2-0.025)((x-2)^2+(y-1)^2-0.025)=0 [-10, 10, -2, 8]}