How do you graph #2x + 3y = 12# by plotting points?

1 Answer
Mar 27, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(2 * 0) + 3y = 12#

#0 + 3y = 12#

#3y = 12#

#(3y)/color(red)(3) = 12/color(red)(3)#

#y = 4# or #(0, 4)#

Second Point: For #y = 0#

#2x + (3 * 0) = 12#

#2x + 0 = 12#

#2x = 12#

#(2x)/color(red)(2) = 12/color(red)(2)#

#x = 6# or #(6, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x + 3y - 12)(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}