# How do you graph #2x + 3y = 12# by plotting points?

##### 1 Answer

Mar 27, 2018

See a solution process below:

#### Explanation:

First, solve for two points which solve the equation and plot these points:

**First Point:** For

**Second Point:** For

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x + 3y - 12)(x^2+(y-4)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}