How do you graph 2x+3y=-2?

1 Answer
Jan 20, 2018

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For x = 2

(2 * 2) + 3y = -2

4 + 3y = -2

4 - color(red)(4) + 3y = -2 - color(red)(4)

0 + 3y = -6

3y = -6

(3y)/color(red)(3) = -6/color(red)(3)

y = -2 or (2, -2)

Second Point: For y = 0

2x + (3 * 0) = -2

2x + 0 = -2

2x = -2

(2x)/color(red)(2) = -2/color(red)(2)

x = -1 or (-1, 0)

We can next plot the two points on the coordinate plane:

graph{((x-2)^2+(y+2)^2-0.04)((x+1)^2+y^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{((x-2)^2+(y+2)^2-0.04)((x+1)^2+y^2-0.04)(2x + 3y + 2)=0 [-10, 10, -5, 5]}