How do you graph #2x+4y=8# by plotting points?

1 Answer
Sep 7, 2017

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(2 * 0) + 4y = 8#
#0 + 4y = 8#
#4y = 8#

#4y/color(red)(4) = 8/color(red)(4)#

#y = 2# or #(0, 2)#

Second Point: For #y = 0#

#2x + (4 * 0) = 8#
#2x + 0 = 8#
#2x = 8#

#(2x)/color(red)(2) = 8/color(red)(2)#

#x = 4# or #(4, 0)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x+4y - 8)(x^2+(y-2)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}