How do you graph #2x+5y=8#?

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Answer 1 · 2017-02-24T18:48:20

graph{2x+5y=8 [-4.72, 5.28, -1.56, 3.44]}

#y=-0.4x+1.6#

y-intercept at #(0,1.6)#
x-intercept at #(4,0)#

convert function to #y=mx+c# form:

#2x+5y=8#

(subtract #2x#)
#5y = 8-2x#
#5y = -2x+8#

(divide by #5#)
#y=(-2x+8)/5#
or
#y=-0.4x+1.6#

from the #y=mx+c# form, you can plot the #y#-intercept at #(0,1.6).#

the graph is negative, so as #x# increases, #y# decreases.

the #x#-intercept is at #(4,0) # since #-0.4*4 = -1.6# and #-1.6 + 1.6 = 0#