How do you graph 2x + y = 3 by plotting points?
1 Answer
Find a few
Explanation:
Pick some values for
For example, if
" "2x+y=3
=>2(0)+y=3
=>" "0+y=3
=>" "y=3
So when
We can get a few more points:
If
" "2x+y=3
=>2(1)+y=3
=>" "2+y=3
=>" "y=1
So
Similarly, if
We then take the points we've computed,
graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)=0 [-10, 10, -5, 5]}
Last, since we know this equation is linear, we just need to connect the dots with a line:
graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)(2x+y-3)=0 [-10, 10, -5, 5]}
And we're done!