# How do you graph #2x + y = 3# by plotting points?

##### 1 Answer

#### Answer:

Find a few

#### Explanation:

Pick some values for

For example, if

#" "2x+y=3#

#=>2(0)+y=3#

#=>" "0+y=3#

#=>" "y=3#

So when

We can get a few more points:

If

#" "2x+y=3#

#=>2(1)+y=3#

#=>" "2+y=3#

#=>" "y=1#

So

Similarly, if

We then take the points we've computed,

graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)=0 [-10, 10, -5, 5]}

Last, since we know this equation is linear, we just need to connect the dots with a line:

graph{((x)^2+(y-3)^2-.02)((x-1)^2+(y-1)^2-.02)((x-2)^2+(y+1)^2-.02)(2x+y-3)=0 [-10, 10, -5, 5]}

And we're done!