How do you graph #2y = 8- 12x#?

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Answer 1 · 2018-04-12T01:32:39

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#2y = 8 - (12 * 0)#

#2y = 8 - 0#

#2y = 8#

#(2y)/color(red)(2) = 8/color(red)(2)#

#y = 4# or #(0, 4)#

Second Point: For #x = 1#

#2y = 8 - (12 * 1)#

#2y = 8 - 12#

#2y = -4#

#(2y)/color(red)(2) = -4/color(red)(2)#

#y = -2# or #(1, -2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.035)((x-1)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2y - 8 + 12x)(x^2+(y-4)^2-0.035)((x-1)^2+(y+2)^2-0.035)=0 [-10, 10, -5, 5]}