How do you graph #36x + 8y = 64#?

1 Answer
Jun 18, 2017

Answer:

You need to isolate for #y#.

Explanation:

You first make sure that #y# is isolated, in order to do so, you divide everything by #8#, or in other cases, the number in front of #y#.

HOW?

Make sure that #8#y is by itself and there's no other numbers beside it, In your case, #36x# is with #8y#, so bring over #36x# to the other side, in doing so, it becomes a negative.

Now you have

#8y = 64 - 36x #

To isolate #y#, you must factor, divide everything by #8# to get #y# by itself.

Now you have

#y = 8 - 4.5x #

Now to graph it, you can just put it in a table of values.
Have 2 columns, one #x#, one #y#, then make #x# whatever you like.

NOTE: It's recommended for #x# to be #-2, -1, 0, 1, 2#

Now just plug each #x# into the equation and that will be your #(x,y)# coordinate.

Example,

#x = -2#

#y = 8 - 4(-2) #

#y = 16 #

Now your coordinates are #(-2, 16)#, then keep doing that until you finish your line.

graph{36x + 8y = 64 [-10, 10, -5, 5]}