How do you graph #3x+3y=3# by plotting points?

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Answer 1 · 2017-10-08T13:38:15

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(3 * 0) + 3y = 3#

#0 + 3y = 3#

#3y = 3#

#(3y)/color(red)(3) = 3/color(red)(3)#

#y = 1# or #(0, 1)#

Second Point: For #y = 0#

#3x + (3 * 0) = 3#

#3x + 0 = 3#

#3x = 3#

#(3x)/color(red)(3) = 3/color(red)(3)#

#x = 1# or #(1, 0)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 3y - 3)(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}