How do you graph 3x-y=5 on a coordinate plane?

Jun 22, 2018

Refer to the explanation.

Explanation:

Graph:

$3 x - y = 5$

This is the standard form for a linear equation: $A x + B y = C$

You only need two points to graph a straight line; the x- and y-intercepts.

X-intercept: value of $x$ when $y = 0$

Substitute $0$ for $y$ and solve for $x$.

$3 x - 0 = 5$

$3 x = 5$

Divide both sides by $3$.

$x = \frac{5}{3}$

Point: $\left(\frac{5}{3} , 0\right)$ or $\left(\approx 1.667 , 0\right)$

Y-intercept: value of $y$ when $x = 0$

Substitute $0$ for $x$ and solve for $y$.

$3 \left(0\right) - y = 5$

$- y = 5$

Multiply both sides by $- 1$.

$y = - 5$

Point: $\left(0 , - 5\right)$

Plot the two points and draw a straight line through them.

graph{3x-y=5 [-10, 10, -7.2, 2.8]}