How do you graph #4(x-2)^2-5#?

1 Answer
Mar 22, 2017

From this equation of #y=4(x-2)^2-5#.
=> We know the vertex of #(2, -5)#.
=> There is a vertical stretch by a factor of #4#.

Explanation:

So what this equation reveals is because it's in vertex form, we can easily graph this quadratic.

From this equation of #y=4(x-2)^2-5#.
=> We know the vertex of #(2, -5)#.
=> There is a vertical stretch by a factor of #4#.

As a result, you'll get this:

Desmos

Hope this helps :)

P.S. You have to include the #y=# component. It's very important to do so or else you do not have a quadratic relation.

P.P.S (?) This graphing program is called Desmos. It's a very good program that I recommend help others visualize when they struggle to.