How do you graph #6x+5y=20#?

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Answer 1 · 2018-01-24T13:47:25

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#(6 * 0) + 5y = 20#

#0 + 5y = 20#

#5y = 20#

#(5y)/color(red)(5) = 20/color(red)(5)#

#y = 4# or #(0, 4)#

Second Point: For #y = -2#

#6x + (5 * -2) = 20#

#6x - 10 = 20#

#6x - 10 + color(red)(10) = 20 + color(red)(10)#

#6x - 0 = 30#

#6x = 30#

#(6x)/color(red)(6) = 30/color(red)(6)#

#x = 5# or #(5, -2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.075)((x-5)^2+(y+2)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(6x+5y-20)(x^2+(y-4)^2-0.075)((x-5)^2+(y+2)^2-0.075)=0 [-20, 20, -10, 10]}