How do you graph $a_n=8(3)^(n-1)$ ?

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Answer 1 · 2018-02-15T07:17:14

By assigning values to n

If n is zero, $a_n = 2.66$
If n is 1, $a_n=8$
When n is 2, $a_n = 24$
When n is 3, $a_n = 72$

etc.

The graph is provided below

graph{8((3)^(x-1)) [-10.71, 9.29, -1.24, 8.76]}

How do you graph a_n=8(3)^(n-1)a_n=8(3)^(n-1)?