Question

How do you graph and convert `-3y = -12+x` into slope-intercept form?

Answer 1

You need a form like `y=mx+b` where `m` is the slope and `(0,b)` the `y`-intercept, so you have to get a single `y` to one side.

Explanation:

Divide both sides by `-3`

`(cancel(-3)*y)/cancel(-3)=(cancel(-3)*4)/cancel(-3)+x/-3`

Result:

`y=-1/3x+4`

You can graph this by noticing that
`y=4ifx=0->(0,4)`
`x=12ify=0->(12,0)`
And then draw a line trough these points.
graph{-1/3x+4 [-4.04, 15.96, -1.32, 8.68]}