How do you graph and solve | 3x-12 |>0?

Aug 25, 2017

$x > 4 \mathmr{and} x < 4$

Explanation:

$| 3 x - 12 | > 0$
We need to solve the absolute value
We know either
$3 x - 12 > 0 \mathmr{and} 3 x - 12 < - 0$
So, we gonna solve the first one or the first possibility
$3 x - 12 > 0$
$3 x > 0 + 12$
$3 x > 12$
Divide both sides by 3
$\frac{3 x}{3} > \frac{12}{3}$
$x > 4$

Now let solve the second one or the second possibility
$3 x - 12 < - 0$
$3 x < - 0 + 12$
$3 x < 12$
Divide both sides by 3
$\frac{3 x}{3} < \frac{12}{3}$
$x < 4$

Thus,
Our final answer is : $x > 4 \mathmr{and} x < 4$ graph{|3x - 12| > 0 [-10, 10, -5, 5]}