# How do you graph and solve |4y+3| -8<= -3?

Oct 17, 2016

#### Answer:

$- 2 \le y \le \frac{1}{2}$

#### Explanation:

Rearranging the equation
∣4y+3∣<=8-3<=5
So we have to solve
∣4y+3∣<=5
The solutions are
$4 y + 3 \le 5$ and $- \left(4 y + 3\right) \le 5$
So we have to solve
$4 y \le 2$ and $- 4 y - 3 \le 5$
$y \le \frac{1}{2}$ and $4 y \ge - 8$ =>$y \ge - 2$
So the solutions are $- 2 \le y \le \frac{1}{2}$
Checking, if y=0
LHS =$3 - 8 = - 5$
RHS =$- 3$
so $L H S \le R H S$