# How do you graph and solve | x-3 | >8 ?

Solution: $x < - 5 \mathmr{and} x > 11$. In interval notation: $\left(- \infty , - 5\right) \cup \left(11 , \infty\right)$
1) $| x - 3 | > 8 \mathmr{and} x - 3 > 8 \mathmr{and} x > 11$ OR
2) $| x - 3 | > 8 \mathmr{and} x - 3 < - 8 \mathmr{and} x < - 5$
Solution : $x < - 5 \mathmr{and} x > 11$ In interval notation: $\left(- \infty , - 5\right) \cup \left(11 , \infty\right)$[Ans]