# How do you graph and solve |x+6| +8 >2?

Nov 24, 2015

See graph: This may not be the full answer as it was a long time ago that I did these. Hope what I have done helps!

#### Explanation:

$| x + 6 |$" is always positive Within the 'absolute' $x$ can take any including $- 6$. At the point of x=-6 ; color(white)(...)|x+6| =0 and this is its minimum value. AS you are always adding 8 the minimum value is $0 + 8 = 8$. Consequently all value of $y > 2$.

Thus all the area above the plot is the feasible region.