How do you graph and solve #|x+6| +8 >2#?

1 Answer
Nov 24, 2015

Answer:

See graph: This may not be the full answer as it was a long time ago that I did these. Hope what I have done helps!

Explanation:

enter image source here

#|x+6| #" is always positive Within the 'absolute' #x# can take any including #-6#. At the point of #x=-6 ; color(white)(...)|x+6| =0# and this is its minimum value. AS you are always adding 8 the minimum value is #0+8=8#. Consequently all value of #y >2#.

Thus all the area above the plot is the feasible region.