# How do you graph and solve |x+6| +8 >2?

$| x + 6 |$" is always positive Within the 'absolute' $x$ can take any including $- 6$. At the point of x=-6 ; color(white)(...)|x+6| =0 and this is its minimum value. AS you are always adding 8 the minimum value is $0 + 8 = 8$. Consequently all value of $y > 2$.