How do you graph and solve |y+8| >3? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Guillaume L. Jun 24, 2018 |y+8|>3 For y> -8, : y+8>3 S_1:y> -5 For y<-8, : -y-8>3 -y>11 S_2:y<-11 Finally, S=S_1uuS_2 S=y in] - oo;-11[ uu ]-5;+oo[ Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 2582 views around the world You can reuse this answer Creative Commons License