How do you graph #f(x)=2*3^x#?

1 Answer

Answer:

See below

Explanation:

Let's first notice that the graph of #3^x# will have a #y-# intercept of 1 (anything taken to the power of 0 is 1). Then at #x=1, y=3# - we have an exponential function's graph, so it'll soar off to the right and approach 0 from the right as #x# becomes more and more negative.

graph{3^x}

This is modified by being multiplied by 2 - everything moves up by a power of 2. The #y-# intercept is now at 2, #x=1=>y=6#, etc.

graph{(2)3^x}