Question

How do you graph `f(x)=-2x-3`?

Answer 1

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For `x = 0`

`f(0) = (-2 * 0) - 3`

`f(0) = 0 - 3`

`f(0) = -3` or `(0, -3)`

Second Point: For `x = -2`

`f(-2) = (-2 * -2) - 3`

`f(-2) = 4 - 3`

`f(-2) = 1` or `(-2, 1)`

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.035)((x+2)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + 2x + 3)(x^2+(y+3)^2-0.035)((x+2)^2+(y-1)^2-0.035)=0 [-10, 10, -5, 5]}