How do you graph #f(x) = x^3-2x-4#?

1 Answer
Jul 23, 2018

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Please read the explanation.

Explanation:

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We are given the Cubic Function: #color(red)(y=f(x)=x^3-2x-4#

To find the y-intercept:

Set #color(blue)((x=0)# to find the corresponding of #color(blue)((y))#

#y=0^3-2(0)-4#

#y=(-4)#

Hence, we understand that #color(blue)((0,-4)# is the y-intercept of the graph of the given cubic function.

To find the x-intercept:

Set #color(blue)((y=0)# to find the corresponding of #color(blue)((x))#

#0=x^3-2(x)-4#

We are unable to factor the cubic function above.

Create a data table with values as shown:

enter image source here

The table on the right hand side, displays #color(red)((y=-4)# when #color(red)((x=0)#

#color(blue)((0,-4)# is the y-intercept of the graph of the given cubic function.

In the table, we can also observe that #color(red)((y=0)# when #color(red)((x=2)#

#color(blue)((2,0)# is one of the x-intercepts of the graph of the given cubic function.

Using an appropriate graphic software or a calculator, we can obtain the graph as shown below:

enter image source here

Hope it helps.