How do you graph #f(x)=-x^3+3x# using zeros and end behavior?
1 Answer
Aug 28, 2017
Explanation:
#"to obtain zeros solve "f(x)=0#
#rArr-x^3+3x=0#
#rArrx(3-x^2)=0#
#rArrx=0,x=+-sqrt3" are the zeroes"#
#"end behaviour of "f(x)#
#f(x)" is degree 3 (odd) with negative leading coefficient"#
#• " as "xto-oo,f(x)to+oo#
#• " as "xto+oo,f(x)to-oo#
graph{-x^3+3x [-10, 10, -5, 5]}