Question

How do you graph `f(x) = (x-4)^2+5`?

Answer 1

here is the graph:

Explanation:

Compare `f(x)=(x-p)^2+q` to `f(x)=(x-4)^2+5`

`vertex= (p,q)`

so, the vertex of the graph is (4,5).
find the point on the graph.

Then draw accordingly.