How do you graph #f(x)=x^5-2# using zeros and end behavior?
1 Answer
Dec 4, 2016
See explanation.
Explanation:
The number of changes in the signs of the coefficients in
f(x) and f(-x) are 1 and 0, respectively.
As the degree of f is odd, we conclude that there is no negative root
and there is exactly one positive root. The other four zeros are
complex, occurring in two conjugate pairs.
Easily, the positive root is 2^(1/5)=1.1487, nearly.
As
The y-intercept ( x = 0 ) is -2.
The x-intercept ( y = 0 ) is 1.1487, nearly.
All this behavior is well illustrated by the inserted graph
There are no asymptotes
graph{x^5-2 [-20, 20, -10, 10]}
