# How do you graph f(x) = (x+5)^2(x+2)(x-1)?

Aug 6, 2018

Below

#### Explanation:

First, find your x- and y-intercepts
When $y = 0$, $x = - 5 , - 2 , 1$
When $x = 0$, $y = - 50$

Notice the $2$ in ${\left(x + 5\right)}^{2}$ which tells you that at $x = - 5$, there is a double root. So what that means is that at $x = - 5$, you should draw a shape that "bounces" off the point.

Also when you expand the beginning of your function, you will notice that you start off with ${x}^{4}$ and the $4$ tells you that it is a form of parabola. Therefore, the ends of your function should be pointing in the same direction

Below is the graph
graph{(x+5)^2(x+2)(x-1) [-10, 10, -5, 5]}