How do you graph of #y=5(2)^x# and state the domain and range?

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Answer 1 · 2016-11-29T03:28:44

Domain: #x -n (-oo, oo)

Range: #y in (0, oo). Graph is inserted

As the exponential function #2^x > 0, y>0#

log y = log 5 + x log 2.

y-intercept = 5.

Limits:

As #x to -oo, y to 0#.

As #x to oo, y to oo#.

x-axis, in the negative direction, is the asymptote.

graph{log y -log 5 -x log 2=0 [-20, 20, -10, 10]}