Question

How do you graph `p= - 2.2\sqrt { t } + 63.8`?

Answer 1

See a solution process below:

Explanation:

Because we cannot take the square root of a negative number the curve will begin at `0` on the `t` or horizontal access and move to the right.

Because the square root of a number produces both a positive AND negative result we will need to determine both the `+-sqrt(t)` values for each point on the `t` or horizontal access:

graph{(y+2.2sqrt(x) - 63.8)(y-2.2sqrt(x) - 63.8)=0 [-1000. 1000, -50, 150]}