# How do you graph #r=4costheta+2#?

##### 1 Answer

Graph is inserted.

#### Explanation:

The period for the graph is

The range for r is [0, 6]>

As

So, the loop of the limacon ( with dimple at the pole ) is drawn for

For

So, the the cartesian form for

the initial line

graph{x^2+y^2-2sqrt(x^2+y^2)-4x=0 [-10, 10, -5, 5]}

The combined graph of four limacons

about the pole, through

graph{(x^2+y^2-2sqrt(x^2+y^2)-4x)(x^2+y^2-2sqrt(x^2+y^2)+4x)(x^2+y^2-2sqrt(x^2+y^2)-4y)(x^2+y^2-2sqrt(x^2+y^2)+4y)=0 [-20, 20, -10, 10]}