How do you graph the inequality #2(2x-1) + 7 < 13#?

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Answer 1 · 2018-05-17T06:24:13

#x<2#
See graphical representation below

#2(2x-1)+7<13#

Expand LHS #->4x-2+7<13#

#4x+5<13#

#4x<13-5#

#4x<8#

Divide through by #4 -> x<2#

#x<2# is represented on the real line by the interval #(-oo, 2)#

This can be represented on the #xy-#plane by the area to the left of the vertical line #x=2# as graph below.

graph{2(2x-1)+7<13 [-10, 10, -5, 5]}