How do you graph the line 3x-4y-8=0?

Aug 9, 2018

you will have to graph the line

$y = \frac{3}{4} x - 2$

where $\frac{3}{4}$ is the gradient of the line and it has a $y$-intercept of $- 2$.

Explanation:

you would have to rearrange the given equation into the

$y = m x + c$

form, where $m$ is the gradient of the straight line and $c$ is the $y$-intercept.

graph{3/4x-2 [-10, 10, -5, 5]}

Aug 10, 2018

As below.

Explanation:

$3 x - 4 y - 8 = 0$

For x = 0, -4y - 8 = 0 " or " y-intercept = -2

For y = 0, 3x = 8 " or " x-intercept = 8/3

Now we know, x intercept as 8/3 and y intercepts as -2#

We can mark the intercepts on the graph and join them to draw the line.

graph{(3/4)x - 2 [-10, 10, -5, 5]}

Aug 10, 2018

Graph the line by finding the intercepts.

Explanation:

Graph:

$3 x - 4 y - 8 = 0$

Add $8$ to both sides of the equation to get the equation into standard form:

$A x + B y = C$, so that

$3 x - 4 y = 8$

You can graph this equation by finding the intercepts.

X-intercept: value of $x$ when $y = 0$

Substitute $0$ for $y$ and solve for $x$.

$3 x - 4 \left(0\right) = 8$

$3 x = 8$

Divide both sides by $3$.

$\frac{3 x}{3} = \frac{8}{3}$

$x = \frac{8}{3}$ or $\approx 2.667$

The x-intercept is $\left(\frac{8}{3} , 0\right)$ or $\approx 2.667$ Plot this point.

Y-intercept: value of $y$ when $x = 0$.

Substitute $0$ for $x$ and solve for $y$.

$3 \left(0\right) - 4 y = 8$

$- 4 y = 8$

Divide both sides by $- 4$.

$\frac{- 4 y}{- 4} = \frac{8}{- 4}$

$y = - \frac{8}{4}$

Simplify.

$y = - 2$

The y-intercept is $\left(0 , - 2\right)$ Plot this point.

Draw a straight line through the points.

graph{3x-4y=8 [-10, 10, -5, 5]}