# How do you graph the line 4x-3y=9?

##### 1 Answer
Mar 10, 2016

The x-intercept for this equation is $\left(2.25 , 0\right)$
The y-intercept is $\left(0 , - 3\right)$
graph{y=(4/3)x-3 [-10, 10, -5, 5]}

#### Explanation:

A quick way to graph a linear equation is to find two points that the graph passes through. The two easiest points to locate are the $x$,
$\left(x , 0\right)$ intercept and the $y$, $\left(0 , y\right)$ intercept. In your equation, substitute $0$ in for the $y$ variable and solve for $x$:
$4 x - 3 y = 9$
$4 x - 3 \left(0\right) = 9$
$4 x - 0 = 9$
$4 x = 9$
$x = 2.25$ The x-intercept is $\left(2.25 , 0\right)$
Next, substitute $0$ in your equation for $x$, and solve for the y intercept.
$4 x - 3 y = 9$
$4 \left(0\right) - 3 y = 9$
$0 - 3 y = 9$
$- 3 y = 9$
y=-3 So the yintercept is $\left(0 , - 3\right)$
Finally ,locate these two intercepts on the $x \mathmr{and} y$ axis and draw the line through the two intercepts.