How do you graph the line #x-2y=6#?

1 Answer
Mar 20, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#0 - 2y = 6#

#-2y = 6#

#(-2y)/color(red)(-2) = 6/color(red)(-2)#

#y = -3# or #(0, -3)#

Second Point: For #y = 0#

#x - (2 * 0) = 6#

#x - 0 = 6#

#x = 6# or #(6, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x - 2y - 6)(x^2+(y+3)^2-0.035)((x-6)^2+y^2-0.035)=0 [-10, 10, -5, 5]}