How do you graph the line #x+y=3#?

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Answer 1 · 2018-04-12T01:34:23

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#0 + y = 3#

#y = 3# or #(0, 3)#

Second Point: For #y = 0#

#x + 0 = 3#

#x = 3# or #(3, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.035)((x-3)^2+y^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x + y - 3)(x^2+(y-3)^2-0.035)((x-3)^2+y^2-0.035)=0 [-10, 10, -5, 5]}