How do you graph the line #Y=3x-4 #?

1 Answer
Jul 19, 2018

Answer:

See a solution process below:

Explanation:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (3 * 0) - 4#

#y = 0 - 4#

#y = -4# or #(0, -4)#

Second Point: For #y = 2#

#y = (3 * 2) - 4#

#y = 6 - 4#

#y = 2# or #(2, 2)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-3x+4)(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}