How do you graph the line #y = 4x + 3#?

1 Answer
Jul 5, 2016

Answer:

graph{4x + 3 [-10, 10, -5, 5]}

Explanation:

There is more than one way of graphing a linear graph, for this equation I would use the y-intercept and the gradient of the line.

When #x = 0# #y= 3# since #4(0) = 0#, therefore the y-intercept is 3.
Start by plotting a point at your y-intercept #(0,3)#.

Then we also know the gradient of the line, this is the '4' before the #x#. Since when the #x# value increase by 1 the #y# value will increase by 4. Since we know #m#(gradient)# = 4# we can now move 1 point across on the #x#-axis and 4 up on the #y#-axis, now plot a point here #(1,7)#

Now that we have at least 2 points #(0,3)# and #(1,7)# we can connect the points drawing a linear graph.