# How do you graph the line y = 4x + 3?

Jul 5, 2016

graph{4x + 3 [-10, 10, -5, 5]}

#### Explanation:

There is more than one way of graphing a linear graph, for this equation I would use the y-intercept and the gradient of the line.

When $x = 0$ $y = 3$ since $4 \left(0\right) = 0$, therefore the y-intercept is 3.
Start by plotting a point at your y-intercept $\left(0 , 3\right)$.

Then we also know the gradient of the line, this is the '4' before the $x$. Since when the $x$ value increase by 1 the $y$ value will increase by 4. Since we know $m$(gradient)$= 4$ we can now move 1 point across on the $x$-axis and 4 up on the $y$-axis, now plot a point here $\left(1 , 7\right)$

Now that we have at least 2 points $\left(0 , 3\right)$ and $\left(1 , 7\right)$ we can connect the points drawing a linear graph.