# How do you graph the point 1 + 2i on a complex plane?

Jan 11, 2017

See the graph and the explanation.

#### Explanation:

graph{(x-1)^2+(y-2)^2-0.01=0 [-10, 10, -5, 5]}

$T h e$or$e t i c a l l y$, a point is zero-dimensional.

Eyebrows might be raised on my statement that a point is a null

vector that can be associated with any arbitrary direction in space

that is chosen to move away, from the point.

Yet, to make it visible, we locate a point by making a dimensional-

dot.

In a computer monitor, a few glowing pixels mark the point. It is

really a point circle that has a befittingly small radius.

In the inserted graph, I have plotted the point

P(1, 2) to represent the complex number (1, 2i) by the circle

${\left(x - 1\right)}^{2} + {\left(y - 2\right)}^{2} = {\left(\frac{1}{10}\right)}^{2}$.