Question

How do you graph the point 1 + 2i on a complex plane?

Answer 1

See the graph and the explanation.

Explanation:

graph{(x-1)^2+(y-2)^2-0.01=0 [-10, 10, -5, 5]}

`The`or`etically`, a point is zero-dimensional.

Eyebrows might be raised on my statement that a point is a null

vector that can be associated with any arbitrary direction in space

that is chosen to move away, from the point.

Yet, to make it visible, we locate a point by making a dimensional-

dot.

In a computer monitor, a few glowing pixels mark the point. It is

really a point circle that has a befittingly small radius.

In the inserted graph, I have plotted the point

P(1, 2) to represent the complex number (1, 2i) by the circle

`(x-1)^2+(y-2)^2=(1/10)^2`.