# How do you graph the quadratic function and identify the vertex and axis of symmetry for y=-1/3(x+1)^2+3?

Apr 5, 2017

Vertex$\to \left(x , y\right) = \left(- 1 , 3\right)$

Axis of symmetry is at $x = - 1$

#### Explanation:

If you were to expand the brackets you would get: $y = - \frac{1}{3} {x}^{2.} \ldots .$
As the coefficient of ${x}^{2}$ is negative the graph is of form $\cap$

The given equation is the vertex form of a quadratic. It is called that as you may read off the vertex coordinates with only a little but of adjustment.

Given:$\text{ } y = - \frac{1}{3} {\left(x \textcolor{red}{+ 1}\right)}^{2} \textcolor{b l u e}{+ 3}$

x_("vertex")=(-1)color(red)(xx(+1) =-1
${y}_{\text{vertex}} = \textcolor{b l u e}{+ 3}$

Vertex$\to \left(x , y\right) = \left(- 1 , 3\right)$

Axis of symmetry is at $x = - 1$