How do you graph the quadratic function and identify the vertex and axis of symmetry for #y=5/4(x-3)^2#?

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Answer 1 · 2018-07-02T20:58:07

Comparing the given equation: #y=5/4(x-3)^2# or #(x-3)^2=4/5y# with the standard form of parabola: #X^2=4AY# we get

#X=x-3, Y=y, A=1/5#

The above parabola will have the vertex at

#X=0, Y=0#

#x-2=0, y=0#

#x=2, y=0#

#\text{Vertex}\equiv(2, 0)#

Now, the axis of symmetry of given parabola

#X=0#

#x-2=0#

#\text{axis of symmetry: }x=2#

Locate the vertex #(2, 0)# & draw the axis of symmetry #x=2# Draw the parabola which intersects the y-axis at #(0, 45/4)#