# How do you graph the quadratic function and identify the vertex and axis of symmetry for y=5/4(x-3)^2?

Comparing the given equation: $y = \frac{5}{4} {\left(x - 3\right)}^{2}$ or ${\left(x - 3\right)}^{2} = \frac{4}{5} y$ with the standard form of parabola: ${X}^{2} = 4 A Y$ we get

$X = x - 3 , Y = y , A = \frac{1}{5}$

The above parabola will have the vertex at

$X = 0 , Y = 0$

$x - 2 = 0 , y = 0$

$x = 2 , y = 0$

$\setminus \textrm{V e r t e x} \setminus \equiv \left(2 , 0\right)$

Now, the axis of symmetry of given parabola

$X = 0$

$x - 2 = 0$

$\setminus \textrm{a \xi s o f s y m m e t r y :} x = 2$

Locate the vertex $\left(2 , 0\right)$ & draw the axis of symmetry $x = 2$ Draw the parabola which intersects the y-axis at $\left(0 , \frac{45}{4}\right)$