How do you graph the quadratic function and identify the vertex and axis of symmetry and x intercepts for $y=-(x+3)(x+5)$ ?

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Answer 1 · 2017-12-28T06:40:00

x-intercepts: $x=-5 and x=-3$
Axis of Symmetry: $x=-4$
Vertex: $(-4,1)$

x-intercepts:
Use the Null Factor Law
$x+3=0$
$x=-3$
and
$x+5=0$
$x=-5$

Axis of Symmetry:
Halfway between the two x-intercepts.
$x=(-3+(-5))/2=-4$

Vertex:
The function evaluated at the axis of symmetry
$f(-4)=-(-4+3)(-4+5)=1$
Vertex: $(-4,1)$

How do you graph the quadratic function and identify the vertex and axis of symmetry and x intercepts for y=-(x+3)(x+5)y=-(x+3)(x+5)?