How do you graph the quadratic function and identify the vertex and axis of symmetry for #y=(x-1)^2+2#?

1 Answer
Feb 22, 2017

Explained below


The given equation is already in vertex form. Vertex is x=1 and y=2 that is (1,2).
Axis of symmetry is x=1

Since the coefficient of #x^2# is positive, the parabola would open up.

For manual graphing, since vertex is already identified, plot the vertex, draw the axis of symmetry. Identify y-intercept, by putting x=0, so that it would be one y intercept , y=3. There would be no x intercepts. Identify a few other y -values for corresponding x values. Plot these points and with the axis of symmetry, fairly correct graph can be drawn.