How do you graph the solution of #-3( r - 4) \geq 0# on a number line?

1 Answer
Oct 4, 2017

See a solution process below:

Explanation:

Before we graph the inequality we must first solve it for #r#. First, divide each side of the inequality by #color(blue)(-3)# to eliminate the need for the parenthesis. However, because we are multiplying or dividing an inequality by a negative number we must reverse he inequality operator.

#(-3(r - 4))/color(blue)(-3) color(red)(<=) 0/color(blue)(-3)#

#(color(blue)(cancel(color(black)(-3)))(r - 4))/cancel(color(blue)(-3)) color(red)(<=) 0#

#r - 4 color(red)(<=) 0#

Now, add #color(blue)(4)# to each side of the inequality to solve for #r# while keeping the inequality balanced:

#r - 4 + color(blue)(4) color(red)(<=) 0 + color(blue)(4)#

#r - 0 color(red)(<=) 4#

#r <= 4#

To graph this we will draw a vertical line at #4# on the horizontal axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the left side of the line because the inequality operator also contains a "less than" clause:

graph{x <= 4 [-10, 10, -5, 5]}