How do you graph the solution to $- 3 (p - 7) \geq 21$ $-3(p-7)>=21$ on a number line?

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How do you graph the solution to $- 3 (p - 7) \geq 21$ $-3(p-7)>=21$ on a number line?

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Answer 1 · 2017-03-11T13:57:03

$p \geq 0$ $p>=0$

Explanation:

Distribute the bracket.

$- 3 p + 21 \geq 21$ $-3p+21>=21$

$Isolate - 3 p by subtracting 21 from both sides$ $"Isolate "-3p" by subtracting 21 from both sides"$

$=3pcancel(+21)cancel(-21)>=21-21$

$rArr-3p>=0$

$rArrp>=0" is the solution"$

To show the solution on a number line. Place a $color(blue)"filled in circle"$ at zero. This indicates the solution can equal zero. Draw an $color(blue)"arrowed line"$ from zero to the right indicating the direction of the solution.

If not equal to zero we use an $color(blue)"open circle"$ at zero.

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How do you graph the solution to $- 3 (p - 7) \geq 21$ $-3(p-7)>=21$ on a number line?

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Explanation:

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How do you graph the solution to -3(p-7)>=21−3(p−7)≥21-3(p-7)>=21 on a number line?

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How do you graph the solution to $- 3 (p - 7) \geq 21$ $-3(p-7)>=21$ on a number line?