# How do you graph -x + 3y = -9 by plotting intercepts?

The intercepts are found where $y = 0$ and $x = 0$
To find the y-intercept we make $x = 0$. Thus $3 y = - 9$, and so $y = - 3$. This means that the straight line passes through the point $\left(0 , - 3\right)$. Similarly, when $y = 0$ we have $- x = - 9$, that is $x = 9$, so the line passes through $\left(9 , 0\right)$. Now, you need to plot the two points, and draw the line through them.