How do you graph #-x + 3y = -9# by plotting intercepts?

1 Answer
Jul 3, 2016

Answer:

The intercepts are found where #y=0# and #x=0#

Explanation:

To find the y-intercept we make #x=0#. Thus #3y=-9#, and so #y=-3#. This means that the straight line passes through the point #(0, -3)#. Similarly, when #y=0# we have #-x=-9#, that is #x=9#, so the line passes through #(9, 0)#. Now, you need to plot the two points, and draw the line through them.

graph{1/3x-3 [-10, 10, -5, 5]}