How do you graph #x+4y=12# by plotting points?

1 Answer
May 1, 2017

Answer:

One way is to find #x# and #y#-intercepts. Then connect the two points to form your graph.

Explanation:

I noticed that the equation is linear (a degree of #1# on variable), therefore, graphing would be easy.

What we can do is to sub each variable as #0# and solve for the other.

This will give us the #x# and #y#-intercepts.

First, the #x#-intercept:

#x+4y=12#

#x+4(0)=12#

#x=12#

Therefore, the #x#-intercept is #(12, 0)#.


Now the #y#-intercept -

#x+4y=12#

#(0)+4y=12#

#4y=12#

Now we can isolate #y#.

#(4y)/4=12/4#

#y=3#

Therefore, the #y#-intercept is #(0, 3)#.

Now that we have two points, we can just connect the two with a straight line and we have our graph.

graph{x+4y=12 [-10, 10, -5, 5]}

Hope this helps :)