# How do you graph x+4y=12 by plotting points?

May 1, 2017

One way is to find $x$ and $y$-intercepts. Then connect the two points to form your graph.

#### Explanation:

I noticed that the equation is linear (a degree of $1$ on variable), therefore, graphing would be easy.

What we can do is to sub each variable as $0$ and solve for the other.

This will give us the $x$ and $y$-intercepts.

First, the $x$-intercept:

$x + 4 y = 12$

$x + 4 \left(0\right) = 12$

$x = 12$

Therefore, the $x$-intercept is $\left(12 , 0\right)$.

Now the $y$-intercept -

$x + 4 y = 12$

$\left(0\right) + 4 y = 12$

$4 y = 12$

Now we can isolate $y$.

$\frac{4 y}{4} = \frac{12}{4}$

$y = 3$

Therefore, the $y$-intercept is $\left(0 , 3\right)$.

Now that we have two points, we can just connect the two with a straight line and we have our graph.

graph{x+4y=12 [-10, 10, -5, 5]}

Hope this helps :)